21-01-2016, 08:00 PM
btw,
The frame span I posted (previous graphic) from CE884 of extant z186-z207 equals a 20.3ft span over 21 frames.
20.3/21=.966ft per frame traveled.
It takes 4 frames to get from z186-z190.
4 x .966 = 3.864ft
Z186 = Station# 3+50.8 + (3.86ft- 4 frames=z190)=Station# 3+54.66
This puts the possible Breneman vertical error within approx 1inch of where z190 was defined by CE884.
354.74 vs. 354.66 = .08ft=almost 1 inch
Among the other evolving info.
chris
The frame span I posted (previous graphic) from CE884 of extant z186-z207 equals a 20.3ft span over 21 frames.
20.3/21=.966ft per frame traveled.
It takes 4 frames to get from z186-z190.
4 x .966 = 3.864ft
Z186 = Station# 3+50.8 + (3.86ft- 4 frames=z190)=Station# 3+54.66
This puts the possible Breneman vertical error within approx 1inch of where z190 was defined by CE884.
354.74 vs. 354.66 = .08ft=almost 1 inch
Among the other evolving info.
chris